What is the result of executing the following fragment of code:

boolean b1 = false;
boolean b2 = false;
if (b2 != b1 = !b2){
System.out.println("true");
}else{
System.out.println("false");
}

Select 1 option

A. Compile time error.
B. It will print true.
C. It will print false.
D. Runtime error.
E. It will print nothing.

Which line, if any, will give a compile time error?

void test(byte x){
switch(x){
case 'a': // 1
case 256: // 2
case 0: // 3
default : // 4
case 80: // 5
}
}

Select 1 option

A. Line 1 as 'a' is not compatible with byte.
B. Line 2 as 256 cannot fit into a byte.
C. No compile time error but a run time error at line 2.
D. Line 4 as the default label must be the last label in the switch statement.
E. There is nothing wrong with the code.

What will the following code print?

boolean flag = true;
if(flag = false){
System.out.println("1");
}else if(flag){
System.out.println("2");
}else if(!flag){
System.out.println("3");
}else System.out.println("4");

Select 1 option

A. 1
B. 2
C. 3
D. 4
E. Compilation error.

Consider the following method...

public void ifTest(boolean flag){
if (flag) //1
if (flag) //2
System.out.println("True False");
else // 3
System.out.println("True True");
else // 4
System.out.println("False False");
}

Which of the following statements are correct?

Select 3 options

A. If run with an argument of 'false', it will print 'False False'
B. If run with an argument of 'false', it will print 'True True'
C. If run with an argument of 'true', it will print 'True False'
D. It will never print 'True True'
E. It will not compile.

The following method will compile and run without any problems.

public void switchTest(byte x){
switch(x){
case 'b': // 1
default : // 2
case -2: // 3
case 80: // 4
}
}

Select 1 option

A. True
B. False