Multiple Choice Question

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Submitted by c-admin on Tue, 05/28/2019 - 00:14

QID:

Type:

Multiple Choice Question

Category:

Java Programmer I

Tags:

Data Types and Variables

Question:

What happens when you try to compile and run the following class...

public class TestClass{
public static void main(String[] args) throws Exception{
int a = Integer.MIN_VALUE;
int b = -a;
System.out.println( a+ " "+b);
}
}

Select 1 option

A. It throws an OverFlowException.
B. It will print two same negative numbers.
C. It will print two different negative numbers.
D. It will print one negative and one positive number of same magnitude.
E. It will print one negative and one positive number of different magnitude.

Answer and Explanation (Click to expand)

Answer:

Explanation:

It prints: -2147483648 -2147483648

This happens because negative integers are stored in 2's complement form (complement the bits and add 1). For example:
Integer 1 in binary is 00000000 00000000 00000000 00000001 (32 bits)
So -1 in binary would be (complement the bits for 1 and add 1) :
Step 1 (complement the bits of 1): 11111111 11111111 11111111 11111110
Step 2 (add 1 to step 1): 11111111 11111111 11111111 11111111.

Now, let's see what happens in this question:

a = Integer.MIN_VALUE = 10000000 00000000 00000000 00000000

To get -a, apply the above two steps:

Step 1 (complement the bits): 011111111 11111111 11111111 11111111
Step 2 (add 1) : 10000000 00000000 00000000 00000000
So you got the exact same value that you started with!
(Note that you can see the binary form of an integer using Integer.toBinaryString(i) method.)

Q&A Set:

Set 4

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