Inorder Traversal Without Using Recursion

Approach

We can use a stack data structure to do this:

  • Initialize current node as root

  • Create a stack.

  • Do following until current is NULL and stack is empty:

    • Push the current node to stack and set current = current.left until current is NULL

    • If current is NULL and stack is not empty then 

      • Pop the top item from stack into current.

      • Print current,

      • Set current = current.right 

 

Solution

void inorder(TreeNode n)

{

  TreeNode current = n;

  Stack s = new Stack();

  while((current ! = null) || !s.isEmpty())

  {

    if(current!=null)

    {

      s.push(current);

      current = current.left;

    }

    else{

      current = s.pop();

      print(current);

      current = current.right;

    }

  }

}

 

Complexity

Time complexity is O(n)

Extra space for stack also will be taken.

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